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### Question

Activity 3 Problem Solving: Unleash Your Inner Physicisti Directions: Read and analyze the given situation. Solve the following problems systematically using the G.E.S.A. Given, Equation/ Formula, Solution, Answer) method. Express your answer in whole number and box your final answer. 1. While walking to school, you observed a hanging kite with approximate mass of 0.25 kg on a 3 m high tree. As soon as you arrived home, you computed its gravitational potential energy. What would be the answer? G S: E A 2. How high must a sack of sugar weighing 10 kg be lifted to have 58 J of potential energy? (Hint: Derive the formula of PE-mgh to get the formula for height. Divide both sides by the variable/s adjacent to height (h) to get h=) S G: A E: 3. If a bicycle with a velocity of 17.89 has kinetic energy of 5000 J. What is the mass of the bicycie? (Hint: Derive the formula of KE my to get the formula for mass. Divide both sides by the variable/s adjacent to the mass (h) to get me TO S: G: A: E:

### Answer #1 for Questions: Activity 3 Problem Solving: Unleash Your Inner Physicisti Directions: Read and analyze the given situation. Solve the following problems systematically using the G.E.S.A. Given, Equation/ Formula, Solution, Answer) method. Express your answer in whole number and box your final answer. 1. While walking to school, you observed a hanging kite with approximate mass of 0.25 kg on a 3 m high tree. As soon as you arrived home, you computed its gravitational potential energy. What would be the answer? G S: E A 2. How high must a sack of sugar weighing 10 kg be lifted to have 58 J of potential energy? (Hint: Derive the formula of PE-mgh to get the formula for height. Divide both sides by the variable/s adjacent to height (h) to get h=) S G: A E: 3. If a bicycle with a velocity of 17.89 has kinetic energy of 5000 J. What is the mass of the bicycie? (Hint: Derive the formula of KE my to get the formula for mass. Divide both sides by the variable/s adjacent to the mass (h) to get me TO S: G: A: E:

**Answer:**

1. Given:

m = 0.25 kg

h = 3m

g = 9.8 m/[tex]s^{2}[/tex]

Equation:

** GPE = mgh**

Solution:

GPE = mgh

= 0.25 kg x 9.8 m/[tex]s^{2}[/tex] x 3m

= **7.35 Nm or 7.35 J**

** = 7 J**

2. Given:

m = 10 kg

PE – 58 J

g = 9.8 m/[tex]s^{2}[/tex]

Equation:

** PE = mgh **

Derived formula:** h = **[tex]frac{PE}{mg}[/tex]** **

Solution:

h = [tex]frac{PE}{mg}[/tex]

= [tex]frac{58J}{(10kg)(9.8m/s^2}[/tex]

= [tex]frac{58J}{98kgm/s^2}[/tex]

**= 0.59 m**

** = 1 m**

3. Given

v = 17.89 m/s

KE = 5000J

g = 9.8 m/[tex]s^{2}[/tex]

Equation:

**KE = **[tex]frac{1}{2}[/tex]** m**[tex]v^{2}[/tex]

Derived formula: **mass = **[tex]frac{2KE}{v^2}[/tex]

Solution:

mass = [tex]frac{2KE}{v^2}[/tex]

= [tex]frac{2(5000J)}{(17.89m/s)^2}[/tex]

= **31.24 kg**

** = 31 kg**

Explanation

**Energy is the object’s capacity to do work. **There are two major types of energy – potential and kinetic energy. **Potential energy is the energy at rest or the stored energy. **One type of potential energy is the **gravitational potential energy** which is the energy because of the object’s position. The formula to solve for potential energy, **PE = mgh**. It means that potential energy is affected by the object’s mass, height, and pull of gravity. **Kinetic energy is the energy in motion.** It has the formula, **KE = **[tex]frac{1}{2}[/tex]** m**[tex]v^{2}[/tex]**.** It means that the kinetic energy is influenced by the object’s mass and square of the velocity of the object.

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